To solve the following:

1.21 = (1.1)^n

You know that the inverse of exponentiation is the logarithm, so take the log (base 10) or ln (base *e*) or whatever base of both sides. For fun we'll take it to base 10.

log(1.21) = n * log(1.1)

now divide both sides by log(1.1) to get:

log(1.21)/log(1.1) = n

Use your calculator to divide log(1.21) by log(1.1) and find the result "2", So...

n = 2

The trick here is to know that when you take the log(a^n) you get n * log(a). You can then divide by log(a) to get "n" by itself.

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